Answer:
Answer is B. 36 degrees
Step-by-step explanation:
From the diagram,
angle WBY = 2 × angle WXY
angle WBY = 72°
angle WXY =
Answer:
10
65
36
90 - x
Step-by-step explanation:
90 - 80 = 10
90 - 25 = 65
90 - 54 = 36
90 - x
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
Answer:
8+7=15 15x150=0.1
Step-by-step explanation:
Part 1)
we know that
the property of cyclic quadrilaterals for which opposite angles are supplementary
then
m∠A°+43°=180°------------> m∠A=180°-43°=137°
the answer is m∠A=137°
Part 2) <span>Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A?
we know that
</span>the property of cyclic quadrilaterals<span> for which opposite angles are supplementary
then:</span>
<span>m∠A+m∠C=<span>180<span>∘
(2x+9)+(3x+1)=180---------------> 5x+10=180
x=(180-10)/5=34
</span></span></span>m∠A=2x+9-------------> 2*34+9=77°
<span>
the answer is </span>m∠A=77°<span>
</span>
