The standard form of the quadratic function in this problem is given as follows:
y = -0.25(x² - 4).
<h3>How to define the quadratic function?</h3>
The standard definition of a quadratic function is given as follows:
y = ax² + bx + c.
Considering it's roots x' and x'', the definition are given as follows:
y = a(x - x')(x - x'')
In which a is the leading coefficient.
From the table given by the image at the end of the answer, the roots are given as follows:
x' = -2, x'' = 2.
(as they are the values of x for which y = 0).
Then:
y = a(x + 2)(x - 2)
y = a(x² - 4).
When x = 0, y = 1, hence the leading coefficient is given as follows:
1 = -4a
a = -1/4.
a = -0.25.
Hence the equation is of:
y = -0.25(x² - 4).
<h3>Missing Information</h3>
The table is given by the image shown at the end of the answer.
More can be learned about quadratic functions at brainly.com/question/24737967
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