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jasenka [17]
4 years ago
7

Sherri bought 45 cupcakes for a party she was having. If 60% of the cupcakes, were chocolate, how many cupcakes were chocolate?

Mathematics
2 answers:
Veseljchak [2.6K]4 years ago
4 0
27 cupcakes were chocolate
djyliett [7]4 years ago
3 0
27 cupcakes were chocolate
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Find the value of the variable. If your answer is not an integer, leave it in simplest radical form.
AlekseyPX

Answer:

$\frac{5\sqrt{2} }{2}$

Step-by-step explanation:

x: \text{opposite side of the angle of 45\º}

5: \text{hypotenuse of the right triangle}

$\sin(\theta)=\frac{\text{opp}}{\text{hyp}} \Rightarrow \sin(45\º)=\frac{x}{5} $

$\text{Once }\sin(45\º)=\frac{\sqrt{2} }{2} $

$\frac{\sqrt{2} }{2} =\frac{x}{5} \Rightarrow 2x=5\sqrt{2} \Rightarrow x=\frac{5\sqrt{2} }{2}  $

You can just remember that 5 is the diagonal of a square of side length x.

$5=x\sqrt{2} \Rightarrow x=\frac{5}{\sqrt{2} } \Rightarrow x=\frac{5}{\sqrt{2} } \cdot \frac{\sqrt{2} }{\sqrt{2} } = \frac{5\sqrt{2} }{2} $

5 0
4 years ago
Are two pairs of congruent angles enough information to conclude that two triangles are similar
Brilliant_brown [7]
Yes, two pairs of congruent angles is enough information
7 0
3 years ago
Write the following as a complex number in the form a + bi square root -245
Pepsi [2]

Answer:

Step-by-step explanation:

√(-245)=√(49×5×i^2)=7√5 i=0+7√5 i

5 0
4 years ago
Read 2 more answers
What if the simplest form of the radical expression?
patriot [66]

Answer:

\large\boxed{\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}=-\dfrac{7+2\sqrt{10}}{3}}

Step-by-step explanation:

\text{Use}\ (a-b)(a+b)=a^2-b^2\ \text{and}\ (a+b)^2=a^2+2ab+b^2\\\\\\\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}=\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}\cdot\dfrac{\sqrt2+\sqrt5}{\sqrt2+\sqrt5}=\dfrac{(\sqrt2+\sqrt5)^2}{(\sqrt2)^2-(\sqrt5)^2}\\\\=\dfrac{(\sqrt2)^2+2(\sqrt2)(\sqrt5)+(\sqrt5)^2}{2-5}=\dfrac{2+2\sqrt{(2)(5)}+5}{-3}\\\\=-\dfrac{7+2\sqrt{10}}{3}

6 0
4 years ago
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