4 years ago

Sherri bought 45 cupcakes for a party she was having. If 60% of the cupcakes, were chocolate, how many cupcakes were chocolate?

2 answers:

4 0

27 cupcakes were chocolate

3 0

27 cupcakes were chocolate

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alexandr1967 [171]

4w+5+33=90
4w=90-5-33
4w=52
w=13

6 0

3 years ago

Alexandra [31]

Without accurate calculations i would say 50

8 0

3 years ago

avanturin [10]

$3^{2c} + 1 = 28\times3^c - 9 \implies 3^{2c} - 28\times3^c = -10$

Complete the square on the left side:

$3^{2c} - 28\times3^c = \left(3^{2c}-28\times3^c+14^2\right)-14^2 = \left(3^c-14\right)^2 - 196$

Then the equation becomes

$\left(3^c-14\right)^2 - 196 = -10 \\\\ \left(3^c-14\right)^2 = 186 \\\\ 3^c - 14 = \pm\sqrt{186} \\\\ 3^c = 14\pm\sqrt{186}$

Both 14 + √186 and 14 - √186 are positive numbers, so we can take the logarithm (base 3) of both sides without issue:

$\log_3\left(3^c) = c = \log_3\left(14\pm\sqrt{186}\right)$

Then in increasing order, the solutions are

<em>c</em> = log₃(14 - √186), <em>c</em> = log₃(14 + √186)

3 0

3 years ago

BabaBlast [244]

Answer:

id say -1 though not enough details

Step-by-step explanation:

3 0

4 years ago

Lynna [10]

15/x=50/60

Cross multiply

50x=900

Divide

x=18

5 0

3 years ago