how much of brand A fruit punch (20% fruit juice) must be mixed with 9 L of brand b fruit punch (40% fruit juice) to create a m

Question

11 months ago

14

ixture contains 32% fruit juice ?

1 answer:

leonid [27] · Answer 1 · 2024-09-19T15:14:52+03:00

6 liters of brand A fruit punch must be mixed with 9 L of brand b fruit punch.

Let x=liters of Brand A fruit punch to be mixed with 9 liters of Brand B fruit punch.

x + 9 = liters of mixture.

20%(x) + 9*40% = 32%(x+9)

20/100 x + 9*40/100 = 32/100 (x+9)

0.2x + 360/100 = 0.32x + 9*0.32

0.2x + 3.6 = 0.32x + 2.88

0.12x = 3.6 - 2.88

0.12x = 0.72

divide by 0.12 on both sides

x = 0.72/0.12

= 72/100/12/100

= 72/12

= 6 liters.

Therefore 6 liters of brand A fruit punch must be mixed with 9 L of brand b fruit punch.

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￼how much of brand A fruit punch (20% fruit juice) must be mixed with 9 L of brand b fruit punch (40% fruit juice) to create a m