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Sever21 [200]
3 years ago
6

What are the solutions of the quadratic equation? 4x^2+9x-9=0

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

The solutions of the quadratic equation 4x²+9x-9 =0 is x= ³/₄ and x = -3

<h3>Further explanation</h3>

4x²+9x-9 =0

From the above equation a=4, b=9 and c = -9

We can solve the equation using this formula:

\boxed {x = \frac{-b \pm \sqrt{b^{2}-4ac } }{2a} }\\\boxed {x=\frac{-9 \pm\sqrt{81-(4 \times4 \times(-9))} }{8} }\\\boxed {x= \frac{-9 \pm\sqrt{225} }{8} } \\\boxed {x=\frac{-9+15}{8} =\frac{6}{8} =\frac{3}{4} }

and

\boxed {x= \frac{-9-15}{8} = \frac{-24}{8} = -3 }

so the solution is x = \frac{3}{4} or x = -3

<h3>Learn more</h3>

Quadratic equation brainly.com/question/2375877

Quadratic equation brainly.com/question/3843409

Keywords: quadratic equation, quadratic solutions

vagabundo [1.1K]3 years ago
5 0

Answer:

x=3/4

x=-3

Step-by-step explanation:

we have

4x^2+9x-9=0

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^2+9x-9=0

so

a=4\\b=9\\c=-9

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(4)(-9)}} {2(4)}

x=\frac{-9(+/-)\sqrt{225}} {8}

x=\frac{-9(+/-)15} {8}

x=\frac{-9+15} {8}=3/4

x=\frac{-9-15} {8}=-3

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