Question

What are the solutions of the quadratic equation? 4x^2+9x-9=0

Answer 1

The solutions of the quadratic equation 4x²+9x-9 =0 is x= ³/₄ and x = -3

Further explanation

4x²+9x-9 =0

From the above equation a=4, b=9 and c = -9

We can solve the equation using this formula:

$\boxed {x = \frac{-b \pm \sqrt{b^{2}-4ac } }{2a} }\\\boxed {x=\frac{-9 \pm\sqrt{81-(4 \times4 \times(-9))} }{8} }\\\boxed {x= \frac{-9 \pm\sqrt{225} }{8} } \\\boxed {x=\frac{-9+15}{8} =\frac{6}{8} =\frac{3}{4} }$

and

$\boxed {x= \frac{-9-15}{8} = \frac{-24}{8} = -3 }$

so the solution is x = $\frac{3}{4}$ or x = -3

Learn more

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Keywords: quadratic equation, quadratic solutions

Answer 2

Answer:

$x=3/4$

$x=-3$

Step-by-step explanation:

we have

$4x^2+9x-9=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4x^2+9x-9=0$

so

$a=4\\b=9\\c=-9$

substitute in the formula

$x=\frac{-9(+/-)\sqrt{9^{2}-4(4)(-9)}} {2(4)}$

$x=\frac{-9(+/-)\sqrt{225}} {8}$

$x=\frac{-9(+/-)15} {8}$

$x=\frac{-9+15} {8}=3/4$

$x=\frac{-9-15} {8}=-3$