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dangina [55]
3 years ago
8

Which equation best represents the model?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0
C is the the answer. Hope this helped
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Calculate the surface area of the figure below.
makvit [3.9K]

Answer:

Step-by-step explanation:

Surface area is the area times all the faces

6 0
3 years ago
Whats between 0.4 and 0.5
nirvana33 [79]
0.45 since it’s

0.41 0.42 0.43 0.44 0.45 0.46 0.47 0.48 0.49
3 0
3 years ago
Read 2 more answers
Select the correct answer​
White raven [17]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every
nydimaria [60]

Answer:

E: 2.00 + 0.75 [ 2r]

Step-by-step explanation:

r represents the number of miles. For each 1/2 mile the taxi will charge and extra free of $0.75. Then, for each mile, the taxi will charge $0.75*2. For example:

For a trip of 1 mile the taxi will charge:

$2.00+$0.75*2

For a trip of 2 miles, the taxi will charge:

$2.00+0.75*4

For a trip of 10 miles, the taxi will charge:

$2.00+$0.75*20

Notice that the variable fee (the one that depends on the number of miles) is $0.75 times the double of miles. In each case the number of miles is multiplied by two. Then the correct answer is E: 2.00 + 0.75 [ 2r]

5 0
3 years ago
Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
3 years ago
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