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1 year ago

ABCD ~ EFGHСBG3140°4.5y2.50°110°DE2.4AHy = [?]EnterCuright 2003 - 2022 Acellus Corporation. All Rights Reserved.

Mathematics

1 answer:

Lemur [1.5K]1 year ago

6 0

Answer:

$y\text{ = 3}$

Explanation:

Here, we want to get the value of y

From the question, we have it that the two shapes are similar

When two shapes are similar, the ratio of their corresponding sides are equal

Thus, we have it that:

$\frac{AB}{CD}\text{ = }\frac{EF}{GH}$

Mathematically, that would be:

$\begin{gathered} \frac{3}{4.5}\text{ = }\frac{2}{y} \\ \\ 3\times\text{ y= 2}\times4.5 \\ y\text{ = }\frac{2\times4.5}{3} \\ \\ y\text{ =3} \end{gathered}$

You might be interested in

You roll a 6-sided die.

Lerok [7]

Answer:

$\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}$

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

We know $1 \cdot 35 = 35$ , so two factors are 1 and 35.
We know $5 \cdot 7 = 35$ , so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be $\frac{2}{6} = \frac{1}{3}$ since there are two factors and 6 possible options.

This means, logically, there is a $\frac{4}{6} = \frac{2}{3}$ chance of not rolling a factor of 35.

Hope this helped!

5 0

3 years ago

Benito spent $1837 to operate his car last year. Some of these expenses are listed below. Benito's only other expense was for ga

77julia77 [94]

I answered this question before. It lacked some data needed to solve this problem.

Operating Expenses
Cost Insurance $972 
Registration $114 
Maintenance $105

1837 - 972 - 114 - 105 = 646 cost of gasoline

646 / 7600 = 0.085 or 8.5 centavos

3 0

3 years ago

Example 1: Calculation of Normal Probabilities Using ????????-Scores and Tables of Standard Normal Areas The U.S. Department of

Molodets [167]

Answer:

i) 0.872

ii) 0.300

iii) 0.76

iv) 0.704

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $261.50 per month

Standard Deviation, σ = $16.25

We are given that the distribution of monthly food cost for a 14- to 18-year-old male is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(Less than $280)

$P( x < 280) = P( z < \displaystyle\frac{280 - 261.50}{16.25}) = P(z< 1.138)$

Calculation the value from standard normal z table, we have,

$P(x < 280) = 0.872 = 87.2\%$

b) P(More than $270)

P(x > 270)

$P( x > 270) = P( z > \displaystyle\frac{270 - 261.50}{16.25}) = P(z > 0.523)$

$= 1 - P(z \leq 0.523)$

Calculation the value from standard normal z table, we have,

$P(x > 270) = 1 - 0.700 = 0.300 = 30.0\%$

c) P(More than $250)

P(x > 250)

$P( x > 250) = P( z > \displaystyle\frac{250 - 261.50}{16.25}) = P(z > -0.707)$

$= 1 - P(z \leq -0.707)$

Calculation the value from standard normal z table, we have,

$P(x > 250) = 1 - 0.240 = 0.76 = 76.0\%$

d) P(Between $240 and $275)

$P(240 \leq x \leq 275) = P(\displaystyle\frac{240 - 261.50}{16.25} \leq z \leq \displaystyle\frac{275-261.50}{16.25}) = P(-1.323 \leq z \leq 0.8307)\\\\= P(z \leq 0.8307) - P(z < -1.323)\\= 0.797 - 0.093 = 0.704 = 70.4\%$