About 99.7% of vehicles whose speeds are between 59 miles per hour and 77 miles per hour.
Empirical rule states that for a normal distribution, 68% lie within one standard deviations, 95% lie within two standard deviations, and 99.7% lie within three standard deviations of the mean.
Given that mean (μ) = 68 miles per hour, standard deviation (σ) = 3 miles per hour.
68% lie within one standard deviation = (μ ± σ) = (68 ± 3) = (65, 71).
Hence 68% of the vehicle speed is between 65 miles per hour and 71 miles per hour.
95% lie within two standard deviation = (μ ± 2σ) = (68 ± 2*3) = (62, 74).
Hence 95% of the vehicle speed is between 62 miles per hour and 74 miles per hour.
99.7% lie within three standard deviation = (μ ± 3σ) = (68 ± 3*3) = (59, 77).
Hence 99.7% of the vehicle speed is between 59 miles per hour and 77 miles per hour.
Find out more at: brainly.com/question/14468516
Answer:
- x = log(y/4)/log(1.0256)
- your answer for y=12 is correct
Step-by-step explanation:
The question is asking you to solve ...
y = f(x)
for x. (In other words, find the inverse function.)
You already did this using a constant for y. Do the same thing with y instead of the constant.
y = 4(1.0256^x)
y/4 = 1.0256^x . . . . . . . divide by 4
log(y/4) = x·log(1.0256) . . . . . take logs
log(y/4)/log(1.0256) = x . . . . . divide by the coefficient of x
Now, you have a model for x in terms of y, which is what the question is asking for.
x = log(y/4)/log(1.0256) . . . . . . . exact expression
When y=12, this is ...
x = log(12/4)/log(1.0256) ≈ 43.46 . . . . weeks
_____
This is a linear equation in log(y), so can be written as such:
x = 91.0912·log(y) -54.8424 . . . . . approximate expression
The answer would be 0.8, because 800 hundreds go into 8 thousandths, but there is only 80 hundreds, so the answer is 0.8 thousandths.
Answer: 0.8 thousandths
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