We have that
<span>If (5x-4+13x=5) --------------> then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>
-8-4y=-5x
-4y=-5x+8
y=5/4x+2
slope= 5/4
y-intercept=(0,2)
Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t = 
t₁ =
= - 5
t₂ =
= 6
Since time can be negative, it took t = 6s for Rose to hit the water.
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