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Evgesh-ka [11]
1 year ago
8

I need to know how to solve this statistics answer

Mathematics
1 answer:
8_murik_8 [283]1 year ago
8 0

Given,

The value of N is 7.

The mean of the data is 13.

Required

The value of sum of the data.

The mean is calculated as,

\begin{gathered} Mean=\frac{\sum_x}{N} \\ 13=\frac{\sum_x}{7} \\ \sum_x=13\times7 \\ \sum_x=91 \end{gathered}

Hence, the value of sum of data is 91.

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SSHA scores Here are the scores on the Survey of Study Habits and Attitudes (SSHA) for 18 first-year college women:154 109 137 1
mihalych1998 [28]

Answer:

Women has better study habit than men.

Step-by-step explanation:

For knowing who has better study habits and attitudes toward learning we have to find the mean of both the women and men data.

The first step is that we only take first 18 values of both women(X) and men(Y) data, to make them of same length

Mean is used to measure the central tendency of data which represents the whole data in the best way. It can be found as the ratio of the sum of all the observations to the total number of observations.  

Calculating all values:

\bar{X} = 141.0556

\bar{Y} = 121.25

Thus, women has better study habit than men. Since Mean of X is larger than Mean of Y.

5 0
3 years ago
(5x+1)3=15x3 que Propiedad pertenece
Aneli [31]

Answer:

Step-by-step explanation:

1) Reagrupar términos.

3(5x + 1) = 15x^3

2) Divide ambos lados por tres.

5x + 1 = 5x^3

3) Mueva todos los términos a un lado.

5x + 1 - 5x^3 = 0

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6 0
2 years ago
Divide $1.30 by 8 and round the quotient to the neatest cent.
jasenka [17]

Answer:

1.30/8 = 0.1625

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Step-by-step explanation:

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3 years ago
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\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }

Remember that:

\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }
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