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lana [24]
3 years ago
9

Simplify this step by step

le=" \frac{-5jk}{35j^2k^2} " alt=" \frac{-5jk}{35j^2k^2} " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
VikaD [51]3 years ago
8 0
\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }

Remember that:

\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }
maria [59]3 years ago
7 0
\dfrac{-5jk}{35j^2k^2}=-\dfrac{1}{7jk}
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Which expression is equivalent to .02m(n - 5) - .02(m + 10)? A) .02mn - .12m - 0.2 B) .02mn + .12m - 0.2 C) .02mn - .12m + 0.2 D
VikaD [51]
The correct answer is A)<span>.02m(n - 5) - .02(m + 10)</span>
7 0
3 years ago
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What is the volume of the right triangular prism?( please input your answer as a number without a unit.)
77julia77 [94]

I hope this helps you

V=Base Area×Height

V=4.8/2×12

V=16×12

V=196

4 0
3 years ago
And
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Answer:

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5 0
3 years ago
The base of a cylindrical candle has an area of
Fudgin [204]

The volume of the cylindrical candle that has a base area of 12.56 inches is 12.56h inches³.

<h3>Volume of of cylinder</h3>

volume of a cylinder = πr²h

where

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Therefore,

volume of a cylinder = πr²h

Area of the base = πr²

Therefore,

Area of the base = 12.56 inches²

volume of the cylindrical candle = 12.56h inches³

learn more on volume here: brainly.com/question/11459769

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7 0
2 years ago
3² +4² = 5²,
AlekseyPX

Answer:

They are all true

Step-by-step explanation:

1. 3² +4² = 5²

3x3 + 4x4 = 5x5

  9   +  16  =  25

25 = 25

-----------------------

2. 6² + 8² = 10²

36 + 64 = 100

100 = 100

------------------

3. 9² + 12² = 15²

81 + 144 = 225

225 = 225

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4. 5² +12² =13²

25 + 144 = 169

169 =169

-------------------

7 0
11 months ago
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