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Brrunno [24]
2 years ago
8

Plot the following ordered pairs on the same Cartesian plane for each one.

Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

A graph of the given ordered pairs has been plotted as shown in the image attached below.

<h3>What is a graph?</h3>

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

<h3>What is an ordered pair?</h3>

An ordered pair can be defined as a pair of two elements that are typically written in a fixed order within parentheses as (x, y), which represents the x-axis (abscissa) and the y-axis (ordinate) on a coordinate plane.

In conclusion, a graph which represents the given ordered pairs shows a discrete function.

Read more on graphs here: brainly.com/question/4546414

#SPJ1

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For a circle with a radius of 6 feet, what is the measurement of the central angle (in degrees) that intercepts an arc with a le
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Answer:

135 degrees

Step-by-step explanation:

step 1

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step 2

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3 0
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Evaluate the expression 7s2 if s = 4. 112 196 742 784
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Step-by-step explanation:


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3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
harkovskaia [24]

Answer:

○\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]

Step-by-step explanation:

You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of \displaystyle -\frac{\sqrt{3}}{2},which gives you \displaystyle -\frac{2\sqrt{3}}{3}.

Extended Information

\displaystyle y-coordinate → sin\:θ \\ x-coordinate → cos\:θ

\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}

I am joyous to assist you anytime.

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