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1 year ago

I need guidance on finding the correct answers because I am confused

Mathematics

1 answer:

Montano1993 [528]1 year ago

6 0

The Solution:

The correct answer is [option 4]

Given:

Required to select the correct statements.

$\Delta ABC\cong\Delta DCB\text{ \lparen Reason: Side-Angle-Side Triangle Congruence Theorem}$

Thus, the correct answer is [option 4]

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Mrs.Rissoto filled her daughters plastic Swimming pool with water .The water level in the pool changed by -8 gallons each hour d

kogti [31]

I thank that the answer is 180

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3 years ago

What is the range of the function f(x) = 3x2 + 6x – 8?

timama [110]

Answer:

Range is {y | y ≥ –11}

Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of $x^{2}$ , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>

The formula for vertex of a parabola is:

Vertex = $(-\frac{b}{2a}, f(-\frac{b}{2a})$

Where,

$a$ is the coefficient of $x^{2}$
$b$ is the coefficient of $x$

From our equation given, $a=3$ and $b=6$

Now, $x$ coordinate of vertex is $x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1$

$y$ coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the $x$ value [ $x=-1$ ] into the equation. So we have:

$3(-1)^{2}+6(-1)-8\\=-11$

Hence, the range would be all numbers greater than or equal to $-11$

Third answer choice is the right one.

6 0

3 years ago

Read 2 more answers

Can anyone help me find the value please?

AURORKA [14]

Answer:

the answer is x=15 cm

Step-by-step explanation:

here the above given figure is a rectangle ABCD with diagonals AC and BD measuring AC= (x+10)cm and BD=(3x-20) cm

Now,

AC=BD

or, 3x-20 = x+10 [ diagonals of a rectangle are equal]

or, 2x = 30

or, x= 15 cm

I HOPE IT WILL HELP YOU!!!

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3 years ago

Write an equation in slope intercept form for the line through the two points

Musya8 [376]

$m= \frac{y2-y1}{x2-x1} \\ \\ m= \frac{-2-2}{2-(-2)} \\ \\ m= \frac{-4}{4} \\ \\ m=-1$

$y=mx+b \\ \\ y=-1x+b$

$(2)=(-1)(-2)+b \\ \\ 2=2+b \\ \\ 0=b$

$y=-1x+0 \\ \\ y=-x$

5 0

3 years ago

-6a-4= -4 (1+7a) Solve for a.

soldi70 [24.7K]

Answer:

$a = 0$