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Schach [20]
3 years ago
8

Using the picture below find the area of the trapezoid ?

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:

(a) 8x-16 cm^2

Step-by-step explanation:

From the given figure of trapezoid:

Height, h=8 cm

Bases, b_1=(x-6)cm \; and \; b_2=(x+2)cm.

Area of the trapezoid,

A=\frac 1 2 h (b_1 + b_2) \\\\=\frac 1` 2 \times 8 ( x-6+x+2) \\\\=4(2x-4) \\\\

=8x-16 cm^2

Hence, option (a) is correct.

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3 years ago
A gardener can increase the number of dahlia plants in an annual garden by either buying new bulbs each year or dividing the exi
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Answer:

Step-by-step explanation:

Part A

If the gardener increases the number of dahlia plants by buying the new bulbs,

Let the equation representing year (x) and number of bulbs purchased (y) is,

y = mx + b

Here, m = Number of plants purchased each year

b = Initial numbers of plants

For x = 0, and y = 6,

6 = m(0) + b

b = 6

For x = 1, y = 56,

56 = m(1) + 6

m = 50

Therefore, equation for this method of increasing the numbers of plants will be,

y = 50x+ 6

Let the equation for the second method of increasing the number of plants is represented by the equation,

y = a(b)ˣ

From the data given in the table,

For x = 0, y = 6

6 = a(b)⁰

a = 6

For x = 1, y = 12

12 = 6(b)¹

b = 2

Therefore, equation representing the second method (By diving the existing bulbs) will be,

y = 6(2)ˣ

Part B

By substituting the value of x = 10 years,

Method - 1

y = 50(10) + 6

y = 506 plants

Method - 2

y  = 6(2)¹⁰

y = 6144 plants

Part C

After 5 years number of plants by method - 1,

y = 50(5) + 6

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After 5 years number of plants by method - 2,

y = 6(2)⁵

y = 192

Similarly, After 10 years number of plants by method - 1,

y = 50(10) + 6

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By method - 2,

y = 6(2)¹⁰

y = 6144

Since, number of plants after 5 years are less by the second method as compared to method 1

But after 10 years second method results the number of plants more than method-1,

Therefore, gardener should adopt method 2 for increasing the numbers of plants.  

6 0
3 years ago
Write the explicit rule,
meriva

Answer:

a_{n} = 20n + 12

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 52 - 32 = 72 - 52 = 92 - 72 = 20

This indicates the sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 32 and d = 20, thus

a_{n} = 32 + 20(n - 1) = 32 + 20n - 20 = 20n + 12

7 0
3 years ago
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