Question

Function gis represented by the equation.g(x)=-20(1/2)^x+10Which statement correctly compares the two functions on the interval [-2, 1]?

Answer 1

First we find the values for the function g in the interval [-2,1].

x = -2

$g(-2)=-20(\frac{1}{2})^{-2}+10=-70$

x = -1

$g(-1)=-20(\frac{1}{2})^{-1}+10=-30$

x = 0

$g(0)=-20(\frac{1}{2})^0+10=-10$

x = 1

$g(1)=-20(\frac{1}{2})^1+10=0$

Statement

Function f is increasing.

Function g is increasing.

Function f is negative.

Function g is negative.

Answer: D. Both functions are increasing, but function g increases at a faster average rate.