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Simora [160]
4 years ago
10

How to calulate how high a tree that is 5m high and shadow is 4m?

Mathematics
1 answer:
Deffense [45]4 years ago
3 0
If you are trying to figure out the distance between the top of the tree and the end of the shadow, use a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the legs of the right triangle.
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
c = √41 = 6.4 meters
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What is the solution to the equation 8+4=2(x-1)?<br> O 5<br> O11/2<br> O 13/2<br> O 7
maks197457 [2]

Answer:

5

Step-by-step explanation:

Simplifying

8 + 4 = 2(x + 1)

Combine like terms: 8 + 4 = 12

12 = 2(x + 1)

Reorder the terms:

12 = 2(1 + x)

12 = (1 * 2 + x * 2)

12 = (2 + 2x)

Solving

12 = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, and all other terms to the right.

Add '-2x' to each side of the equation.

12 + -2x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0

12 + -2x = 2 + 0

12 + -2x = 2

Add '-12' to each side of the equation.

12 + -12 + -2x = 2 + -12

Combine like terms: 12 + -12 = 0

0 + -2x = 2 + -12

-2x = 2 + -12

Combine like terms: 2 + -12 = -10

-2x = -10

Divide each side by '-2'.

x = 5

Simplifying

x = 5

8 0
2 years ago
Read 2 more answers
Help! ASAP ONLY IF YOU KNOW ty!
agasfer [191]

Answer: 115 degrees

Step-by-step explanation:

Since a kite has one pair of opposite angles which are congruent, W and Y must be congruent because X and Z are not.

The sum of the angles in any quadrilateral is 360 degrees. We know two of the angles as 90 degrees and 40 degrees, so the sum of the other two angles must be 360-90-40 = 230 degrees.

We know that W and Y must be equal so each of them is equal to 230/2 degrees = 115 degrees.

4 0
3 years ago
5. Find the lateral area of the cone to the nearest whole number.
Scorpion4ik [409]

Answer:

Step-by-step explanation:

7 0
3 years ago
7v=2v-20 what is the answer
Ierofanga [76]
7v = 2v - 20

First, subtract 2v from both sides. / Your problem should look like: 7v - 2v = -20
Second, simplify 7v - 2v to 5v. / Your problem should look like: 5v = -20
Third, divide both sides by 5. / Your problem should look like: v = - \frac{20}{5}
Fourth, simplify \frac{20}{5} to 4. / Your problem should look like: v = -4

Answer: v = -4


7 0
4 years ago
A plane travels at a speed of 205mph in still air. Flying with a tailwind, the plane is clocked over a distance of 975 miles. Fl
irakobra [83]

Answer:

T1 = 975 / (205 + V)         flying with wind

T2 = 975 / (205 - V)         flying against wind

T2 = T1 + 2

975 * {1 / (205 - V) - 1 / (205 + V)] = 2

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V^2 + 975 V - 42025 = 0          rearranging

V = 41.3

Values of flying are  246.3 and 163.7

Check:  

T1 = 975 / 246.3 = 3.96 hrs

T2 = 975 / 163.7 = 5.96 hrs

6 0
3 years ago
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