Answer: Yes these triangles are similar
Step-by-step explanation:
First lets write down what we know just to make life easier
x=9
TL should be similar to CH
LY should be similar to KH
The angles should be equal due to SAS
So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14
So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14
Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5
Hope this helps.
No. If it has three sides, then it's a triangle, and not a trapezoid.
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>
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5k^3-8-4k^2+5k^2-2+3k^3
Group like terms:
5k^3+3k^3-4k^2+5k^2-8-2
Add similar elements:
5k^3+3k^3+k^2-8-2
Add similar elements:
8k^3+k^2-8-2
Subtract the numbers:
8k^3+k^2-10
Your Answer Is 8k^3+k^2-10
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D ( -3.5 , -1) O ( -3.5 , -3.5) G ( -3.5 , 0)
Total no. of students - 140 students
Total no. of students from all schools= 140+70+35+105=350
school A= 140÷350×100=40./. (multiplying by 100 because it's the total percentage )
School B = 70÷350×100=20./.
School C = 105÷350×100=30./.
School D = 105÷350×100= 10./.
Consisting all the schools percentage it gives 100./.
Hope this helps
