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katrin2010 [14]
3 years ago
14

The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard

deviation of 0.63 mm. Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

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jeka57 [31]

Answer:

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

Step-by-step explanation:

In this question we have to test an hypothesis.

The null and alternative hypothesis are:

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The significance level is assumed to be 0.01.

The sample of size n=80 gives a proportion of p=61/80=0.7625.

The standard deviation is:

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }=\sqrt{\frac{0.87*0.13}{80} }=0.0376

The statistic z is then

z=\frac{p-\pi+0.5/N}{\sigma}=\frac{0.7625-0.87+0.5/80}{0.0376} } =\frac{-10125}{0.0376} =-2.70

The P-value is

P(z

The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

6 0
3 years ago
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qaws [65]
You're asking for three consecutive odd numbers, then
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It is given that, x + x+2+ x+4 = -27
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Answer:

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Step-by-step explanation:

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For B, even numbers are 4/8 or 1/2 of your options. 1/2 of 100 is 50, so your chance of spinning an even number is 50%

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Answer:

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