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deff fn [24]
2 years ago
12

g what process must occur to define an object as a true star? are there any objects that are sometimes placed on an h-r diagram

that are not true stars?
Physics
1 answer:
lesya692 [45]2 years ago
7 0

There must be the presence of Deuterium to define stars. Deuterium fusion, commonly known as deuterium burning, is a nuclear fusion event in which a proton and a deuterium nucleus fuse to generate a helium-3 nucleus in stars and some substellar objects.

The main characteristic that distinguishes genuine stars from ordinary gas-filled balls, or brown dwarfs as they are frequently referred as, is the presence of nuclear fusion at the core. The temperatures are therefore high enough for nuclear fusion to take place, resulting in the fusion of protons to create help. Other items on the h r diagram that aren't necessarily actual stars would be things like white dwarfs and brown dwarfs. Other particles are accepted in the process, but that's kind of the general notion. Particularly for brown dwarfs, they don't actually have fusion taking place. You can plot a star as a point on the H-R diagram once you know its brightness and temperature (or color). With brighter stars positioned higher on the y-axis, plot luminosity.

To learn more about Stars visit here;

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#SPJ4

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how difficult is it to start a heavy lorry moving and to stop it moving? (choose one answer from the image provided)
ale4655 [162]

Answer:

option B

Explanation:

3 0
3 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

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3 0
4 years ago
Help and thanks in advanced
Zanzabum

Answer:

by doing the test over and over again until you get the right results

Explanation:

3 0
3 years ago
How to find initial velocity without time?
77julia77 [94]
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