Answer:
a. We reject the null hypothesis at the significance level of 0.05
b. The p-value is zero for practical applications
c. (-0.0225, -0.0375)
Step-by-step explanation:
Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.
Then we have , , and , , . The pooled estimate is given by
a. We want to test vs (two-tailed alternative).
The test statistic is and the observed value is . T has a Student's t distribution with 20 + 25 - 2 = 43 df.
The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value falls inside RR, we reject the null hypothesis at the significance level of 0.05
b. The p-value for this test is given by 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.
c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)
, i.e.,
where is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So
, i.e.,
(-0.0225, -0.0375)
Answer:
4/5*1/4*c*5=c
Step-by-step explanation:
(4:5)*(1:4*c*5)
4/5*5c/4
Simplify by crossing out the 4s and 5s.
Equals to c
If repetition not permitted 5*4*3*2*1 if it is 5*5*5*5*5
Answer:
it is a straight line on the graph that either goes up or down or diagonolly and its rate of growth stays the same.
Step-by-step explanation:
Cardboard needed to make tube =
Circumference of Circle base (remember the base is hollow therefore there is no area needed.) x Length of Tube
given r = 2.25cm
L = 24cm
Cardboard needed =