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Complete Question
A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point
Answer:
a)8.717km
b) 54.146°
Step-by-step explanation:
(a)how far is the boat from its starting point.
We solve this question using resultant vectors
= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)
Where
Rcos θ = x
Rsinθ = y
= (4cos38,4sin38) + (5cos67,5sin67)
= (3.152, 2.4626) + (1.9536, 4.6025)
= (5.1056, 7.065)
x = 5.1056
y = 7.065
Distance = √x² + y²
= √(5.1056²+ 7.065²)
= √75.98137636
= √8.7167296826
Approximately = 8.717 km
Therefore, the boat is 8.717km its starting point.
(b)calculate the bearing of the boat from its starting point.
The bearing of the boat is calculated using
tan θ = y/x
tan θ = 7.065/5.1056
θ = arc tan (7.065/5.1056)
= 54.145828196°
θ ≈ 54.146°
Answer: -40 feet
Step-by-step explanation: the scuba diver starts at sea level (0) then swims down 30 feet (-30). after a couple minutes, goes down 10 feet more (-40) the scuba diver will now be -40 down from sea level. so it should be -40 because the scuba diver swam that much down.
lmk if this is incorrect, i'm not quit sure if it is or not. if i'm wrong, i'm so sorry!!
:)
0.015*202455 = 3,036.825
3,036.825+750 = 3,786.83
$3,786.83
An equation
what else could it be?
