The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality
red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3
there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality
summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
Median for sample 1 = 142
Median for sample 2 = 134
Step-by-step explanation:
For Sample 1:
For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.
120, 130, 132, 136, 139, 142, 142, 144, 156, 165, 167
The formula for calculating the term which will be median is:
Median= ((n+1)/2)
Here in sample 1, n=11
So, putting n=11 in the formula
= ((11+1)/2)
= (12/2)
=6th term
The sixth term is 142, so
Median of sample 1=142
For Sample 2:
For finding median, the data is first arranged into ascending or descending order. We are arranging the data in ascending order.
112, 112, 113, 114, 125, 134, 141, 145, 146, 163, 165
The formula for calculating the term which will be median is:
Median= ((n+1)/2)
Here in sample 2, n=11
So, putting n=11 in the formula
=((11+1)/2)
=(12/2)
=6th term
The sixth term is 134, so
Median of sample 2=134
Technically a biology question but if you create the chart all 4 types will be Tt because the Male has the genotype of TT so they will each have a large T in each box (like making a multiplication table). and the female has tt so the only possibility is a large T with a small t in all four squares because there are both homogenous genotypes. (the bottom-most answer is the correct answer)
