Question

1 point

Answer 1

The rate of change at which the value of the auto is -950/year.

What is the Rate of Change?

It is said that the rate at which one quantity changes in relation to another is known as the rate of change function.

In simple terms, when calculating the rate of change in one item, the amount of change in another is divided by the comparable amount of change in another.

From the given data of question,

$V(t) = 24000*0.95^{t}$

Then, by definition, the rate of change =$\frac{d(v(t))}{dt} = \frac{d(24000*0.95^{t} )}{dt}$

                                                                 =  $24000*0.95^{t}*ln(0.95)$

For time (t) = 5 years

$\frac{d(v(t))}{dt} = 24000*0.95^{5}*ln(0.95)$

         = 24000*0.7737*(-0.0512)

         = -950

Hence, the rate of change of the value of the auto is -950/year.

To learn more about the rate of change

brainly.com/question/29362528

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