If x=5 and 5=y, then x=y

Darlene Fine wants to have at least $50,000 in her savings account in 10 years. If her account pays 3.6% interest compounded ann

marshall27 [118]

In this problem the question asked is what principal should be invested on a rate of interest of 3.6% for 10 years to get the totals amount as 50000$
the formula for compound interest is
A=P*(1+R/100)^T
we shall replace the formula
50000=X*(1+3.6/100)^10
50000=x*(100/100+3.6/100)^10
50000=x*(103.6/100)^10
50000=X*(1.036)^10
50000=1.4242x
50000/1.4242=X
35107.42=X
hope u found this useful
feel free to check
pls out this as a brainliest answer please

6 0

3 years ago

Kwamee created a coffee blend for his cafe by mixing Kona beans and Fuji beans. Kona beans cost $11 per pound and Fuji beans cos

yKpoI14uk [10]

Let's use K for Kona and F for Fuji. The system of equations has to be a balanced system. For example, you can't mix the number of pounds of beans with the cost for each because pounds and dollars are different and you can only combine like terms...pounds with pounds and dollars with dollars. So let's start with the number of pounds. Since we don't know how much of each he bought we have the 2 unknowns, F and K, but we DO know that he bought 23 pounds total. So the first equation is
K + F = 23
Now let's see what we can do with the dollars. Again, we don't know how much he bought of each kind of coffee, but we do know that Kona beans cost $11 per pound and that Fuji beans cost $7.50 per pound, and we know that he spent a total of $197. So let's set that up:
11K + 7.50F = 197
Those are your 2 equations. It doesn't say you need to solve them, so you're done.

7 0

2 years ago

State weather Korean won is stronger or weaker than the Rand

LuckyWell [14K]

South Korean won is weaker than Rand

4 0

3 years ago

Read 2 more answers

Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist

Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

$\frac{70}{100}\times 60=42$

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

$\frac{75}{100}\times 42=31.5$

Number of students who need help in computer science and enrolled in his class after school hours

$\frac{30}{100}\times 60=18$

Therefore, there are $31.5+18=49.5$ students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

$\frac{49.5}{60}\times 100=82.5\%$

Hence, there are 82.5% after school students who are enrolled in his classes.

6 0

3 years ago

Bo paid bills with 1/2 of his paycheck snd put 1/5 of the remainder in savings. The rest of his paycheck he divided equally amon

Lana71 [14]

For college, 1-1/2-1/5 = 3/10. Divided by 3 children, 3/10 /3 = 1/10

B. 400 = 1/10 of the total (from above), so 400 = x/10. x = 400*10 = 4000

6 0

3 years ago