Question

Find an equation for the line below A(-2,2) B(6,-4)

Answer 1

Given:

The line passes through point (-2,2) and (6,-4).

Explanation:

The equation of line passing through points (x_1,y_1) and (x_2,y_2) is,

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Determine the equation of line passing through points (-2,2) and (6,-4).

$\begin{gathered} y-2=\frac{-4-2}{6-(-2)}(x-(-2)) \\ y-2=\frac{-6}{8}(x+2) \\ y-2=-\frac{3}{4}x-\frac{3}{4}\cdot2 \\ y=-\frac{3}{4}x-\frac{3}{2}+2 \\ =-\frac{3}{4}x+\frac{1}{2} \end{gathered}$

So equation of line is y = -3/4x + 1/2.