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3 years ago

What are a lot of common sixth grade math problems

1 answer:

4 0

These are just a few of the things you will learn in 6th grade. You will learn how to write a two- variable equation, how to identify the graph of an equation, graphing two-variable equations. how to interpret a graph and a word problem, and how to write an equation from a graph using a table, two-dimensional figures,Identify and classify polygons, Measure and classify angles,Estimate angle measurements, Classify triangles, Identify trapezoids, Classify quadrilaterals, Graph triangles and quadrilaterals, Find missing angles in triangles, and a lot more subjects. Find missing angles in quadrilaterals
Sums of angles in polygons
Lines, line segments, and rays
Name angles
Complementary and supplementary angles
Transversal of parallel lines
Find lengths and measures of bisected line segments and angles
Parts of a circle
Central angles of circlesSymmetry and transformations
Symmetry
Reflection, rotation, and translation
Translations: graph the image
Reflections: graph the image
Rotations: graph the image
Similar and congruent figures
Find side lengths of similar figuresThree-dimensional figures
Identify polyhedra
Which figure is being described
Nets of three-dimensional figures
Front, side, and top viewGeometric measurement
Perimeter
Area of rectangles and squares
Area of triangles
Area of parallelograms and trapezoids
Area of quadrilaterals
Area of compound figures
Area between two rectangles
Area between two triangles
Rectangles: relationship between perimeter and area
compare area and perimeter of two figures
Circles: calculate area, circumference, radius, and diameter
Circles: word problems
Area between two circles
Volume of cubes and rectangular prisms
Surface area of cubes and rectangular prisms
Volume and surface area of triangular prisms
Volume and surface area of cylinders
Relate volume and surface area
Semicircles: calculate area, perimeter, radius, and diameter
Quarter circles: calculate area, perimeter, and radius
Area of compound figures with triangles, semicircles, and quarter circlesData and graphs
Interpret pictographs
Create pictographs
Interpret line plots
Create line plots
Create and interpret line plots with fractions
Create frequency tables
Interpret bar graphs
Create bar graphs
Interpret double bar graphs

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2 years ago

How many terms are in the following expression? 2x+4y+8-2

sashaice [31]

Answer:

Step-by-step explanation:

In this expression, the first term is 2x, then 4y, then 8-2 (which simplifies to 6).

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2 years ago

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2 years ago

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Focus on the regression line. Notice how (0,90) and (1,75) are on this line. Compute the slope of the line through those points

Use the slope formula
m = (y2-y1)/(x2-x1)
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3 years ago

The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot

Stells [14]

Answer:

$z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00$

Now we can calculate the p value. Since is a bilateral test the p value would be:

$p_v= P(Z>2) =0.0228$

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

$\hat p=0.75$ estimated proportion of residents favored annexation

$p_o=0.72$ is the value that we want to test

represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:

Null hypothesis: $p\leq 0.72$

Alternative hypothesis: $p > 0.72$

The statistic for this case is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00$

Now we can calculate the p value. Since is a bilateral test the p value would be:

$p_v= P(Z>2) =0.0228$

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

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2 years ago