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Aliun [14]
1 year ago
10

Juan deposited $550 in an account that earned 2.5% simple interest. He did not make additional deposits and he didn't withdraw a

ny money from the account. What was the balance in Juan's investment account after 18 years? (Refer to the digital Reference Material to assist in determining the correct formula.)
Mathematics
1 answer:
Degger [83]1 year ago
3 0

Answer:

$551.25

Step-by-step explanation:

$450 x 7.5% = 33.75

33.75 x 3 = 101.25

101.25 + 450 = 551.25

You might be interested in
Mary who is 13 years old wants to have $8500 to travel to Argentina when she’s 21 years old. She currently has $6439 in savings
marishachu [46]

Answer:

a; she will have $8812

b: It will be enough for her trip

Step-by-step explanation:

In this question, we are tasked with calculating how much a certain value in a savings account that is earning an interest that is compounded annually will be worth.

To calculate this, we use the compound interest formula;

A = P((1+r/n)^{nt}

Where A is the amount after that number of years which of course we want to calculate

P is the principal amount which is the amount we are investing which is $6439 according to the question

r is the interest rate which is 4% = 4/100 = 0.04

t is the time which is 8 years

n is 1 which is the number of times interest will be compounded annually

We plug these values as follows;

A = 6439(1 + 0.04/1)^8

A = 6439(1.04)^8

A = $8,812.22

This amount is greater then the needed $8,500 for the trip and of course it will be enough

8 0
3 years ago
Which of the following lines will have a negative slope? Select all that apply
olganol [36]

Answer:

1, 5

Step-by-step explanation:

-16/4=-4

10/5=2

1/2=1/2

-1/-3=1/3

-1/4/1/2=-1/2

The negative ones are your answer.

6 0
2 years ago
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
Find the slope of the line through the given points (1,6),(-8,-9)
cestrela7 [59]
The answer to the question

6 0
3 years ago
Help ppppppppppppllllllllllllllllsssssssss
marissa [1.9K]

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

<h3>1)</h3>

sin²θ + 1 = cos²θ     incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ  correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ  incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ  = tan²θ

not such pythagorus identity exists

4 0
3 years ago
Read 2 more answers
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