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weeeeeb [17]
3 years ago
12

Solve for x (1 point)

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0
It should be 13 since 13+8 = 21. 21-7 = 13
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What is the value of x?<br><br> Enter your answer, as a decimal, in the box.
Katarina [22]

Answer:

x=50.6cm

Step-by-step explanation:

Triangle MAB is similar to triangle MNP

Since the triangles are similar, the corresponding ratios are in the same proportion.

Therefore we can write the relation;

\frac{|MB|}{|MP|}=\frac{|MA|}{|MN|}


\frac{x}{72.6}=\frac{46.2-14}{46.2}


This implies that;

\frac{x}{72.6}=\frac{32.2}{46.2}


We multiply both sides by 72.6 to get


\frac{x}{72.6}\times 72.6=\frac{32.2}{46.2}\times72.6


\Rightarrow x=50.6


Hence the value of x is 50.6 cm



8 0
3 years ago
Read 2 more answers
How do you do simultaneous equations by the method or substitution?​
ozzi

Answer:

Here's the simplest example possible: let's say x + y = 3 and x - y = 1. Solve the second equation for x by adding y to both sides: (x - y) + y = 1 + y. So x = 1 + y. Take that value of x, and substitute it into the first equation given above (x + y = 3).

5 0
3 years ago
What is equal to 2/4
Travka [436]
Fractions: 4/8, 1/2

Percent: 50%

Decimal: 0.50
8 0
3 years ago
Read 2 more answers
What is x? Options: 81, 57, 143, 66.
jeyben [28]

Answer:

x = 103

Step-by-step explanation:

In my opinion, because x and 77 are the supplementary angles, so 180-77 = x or x+77=180. The answer should be 103......even though it's not in the options (I'm sorry).

3 0
3 years ago
Read 2 more answers
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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