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Brums [2.3K]
1 year ago
10

the vertices of a triangle are P(-5,-7), Q(-3,-4), and R(2,-6)what are the vertices of the image reflected across the x axis

Mathematics
1 answer:
anzhelika [568]1 year ago
8 0

By definition, a Reflection is a transformation in which the figure is flipped over a line of reflection.

When a figure is reflected across the x-axis, the rule you must apply is the following:

(x,y)\rightarrow\mleft(x,-y\mright)

As you can notice, when a point is reflected across the x-axis, the sign of the y-coordinate changes.

In this case, you know that the vertices of the Pre-Image (the triangle PQR) are:

\begin{gathered} P\mleft(-5,-7\mright);Q\mleft(-3,-4\mright);R\mleft(2,-6\mright) \\  \end{gathered}

Then, applying the rule, you get that the vertices of the Image (triangle P'Q'R'), are:

\begin{gathered} P\mleft(-5,-7\mright)\rightarrow P^{\prime}\mleft(-5,7\mright) \\ Q\mleft(-3,-4\mright)\rightarrow Q^{\prime}\begin{pmatrix}-3,4\end{pmatrix} \\ R\mleft(2,-6\mright)\rightarrow R^{\prime}\mleft(2,6\mright) \end{gathered}

The answer is:

\begin{gathered} P^{\prime}(-5,7) \\ Q^{\prime}\begin{pmatrix}-3,4\end{pmatrix} \\ R^{\prime}(2,6) \end{gathered}

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Answer:

The equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

  • y+2=\frac{3}{4}\left(x+4\right)
  • 3x - 4y = -4

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

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Given the line

3x - 4y = 7

writing in the slope-intercept form

4y = 3x - 7

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y = 3/4x - 7/4

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now we have,

The point (-4, -2)

The slope m of parallel line = 3/4

Given the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting (-4, -2) and m = 3/4 in the point-slope form of line equation

\:y-\left(-2\right)=\frac{3}{4}\left(x-\left(-4\right)\right)

y+2=\frac{3}{4}\left(x+4\right)

Thus, the equation in the point-slope form of the line equation is:

y+2=\frac{3}{4}\left(x+4\right)

Simplifying the equation

y+2=\frac{3}{4}\left(x+4\right)

Subtract 3 from both sides

y+2-2=\frac{3}{4}\left(x+4\right)-2

y=\frac{3}{4}x+1

Multiplying the equation by 4

4y = 3x + 4

3x - 4y = -4

Therefore, the equations represent the line that is parallel to 3x - 4y = 7 and pass through the point (-4,-2) are:

  • y+2=\frac{3}{4}\left(x+4\right)
  • 3x - 4y = -4
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