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Ivahew [28]
4 years ago
8

If $n \cdot 1 \cdot \frac{1}{2} \cdot \frac{1}{3} \cdot \frac{1}{4} \cdot \frac{1}{5} = \frac{1}{2} \cdot \frac{1}{4} \cdot \fra

c{1}{6} \cdot \frac{1}{8} \cdot \frac{1}{10}$, what is the value of $n$? Express your answer as a common fraction.
Mathematics
1 answer:
tatuchka [14]4 years ago
8 0

n\cdot1\cdot\dfrac12\cdot\dfrac13\cdot\dfrac14\cdot\dfrac15=\dfrac n{5!}

\dfrac12\cdot\dfrac14\cdot\dfrac16\cdot\dfrac18\cdot\dfrac1{10}=\dfrac{3\cdot5\cdot7\cdot9}{10!}

So we have

\dfrac n{5!}=\dfrac{3\cdot5\cdot7\cdot9}{10!}

n=\dfrac{3\cdot5\cdot7\cdot9}{6\cdot7\cdot8\cdot9\cdot10}

n=\dfrac{3\cdot5}{6\cdot8\cdot10}

n=\dfrac1{2\cdot8\cdot2}

n=\dfrac1{32}

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