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AveGali [126]
1 year ago
14

Tickets to a local movie were sold at $12.00 for general admission and $9.00 for seniors. If 155 tickets were sold for a total o

f $1,680.00, how many general admission tickets were sold?
Mathematics
1 answer:
kondaur [170]1 year ago
7 0

We have a problem of a sysmtem of equation

x is the number tickets sold of general admission

y is the number o tickets sold for seniors

The first equation is about the number of ticktes sold

x+y=155

the second equation is about the amount of money

12x+9y=1680

we isolate x of the first equation

x=155-y

we substitute the equatio above in the second equation

12(155-y)+9y=1680

1860-12y+9y=1680

we isolate the y

-3y=1680-1860

-3y=-180

y=-180/-3

y=60

then we substitute the value of y in order to find x

x=155-y

x=155-60

x=95

They sold 95 tickets of general admission

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Anarel [89]

Answer:

a.) .375 inches per day

b.) no

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Step-by-step explanation:

If 8 days produces 3 inches of ice, I divided the 3 inches by the 8 days to see how much it grew per day. I got<u> .375 inches per day</u>.

Knowing how much it grew each day, I used .375 inches per day and multiplied it by 21 (3 weeks). So <u>no, it only grew 7.875 inches over the 21 days</u>.

You can double check it by dividing 10 inches / .375 inches per day and saw it would take over 26 days to reach 10 inches.

I took 1.5 feet and converted it to 18 inches. 18 inches divided by .375 inches per day equals <u>48 days.</u>

I hope this helps you! :)

4 0
4 years ago
Find the two numbers whose sum is 24 and whose product is as large as possible.
svetlana [45]
Let, the numbers are: x, (24-x)
Let, P(x) denote their products. Then, we have:
P(x) = x(24-x) = 24x - x²
P'(x) = 24-2x
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Now, P'(x) = 0 ⇒ x = 12
Also, 
P''(12) = -2 < 0

So, By second derivative test, x = 12 is the point of local maxima of p. Hence the product of the numbers is the maximum when the numbers are 12 and (24-12) = 12

So, In short that numbers would be 12,12

Hope this helps!
4 0
3 years ago
Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

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We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)

So once we find T(1), we can determine T(x) and T(x^2). We have

T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4

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8 0
3 years ago
Perez Corporation has the following financial data for the years 20X1 and 20X2: 20X1 20X2 Sales $ 8,000,000 $ 10,000,000 Cost of
muminat

Step-by-step explanation:

The computations are shown below:

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For 20X1:

Inventory turnover = Sales ÷ Inventory

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= 10  times

For 20X2:

Inventory turnover = Sales ÷ Inventory

=$8,000,000 ÷  $800,000

= 10  times

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For 20X1:

Inventory turnover = Cost of goods sold ÷ Inventory

= $6,000,000 ÷ $800,000

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For 20X21:

Inventory turnover = Cost of goods sold ÷ Inventory

= $9,000,000 ÷ $1,000,000

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Answer:

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Step-by-step explanation:

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