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nordsb [41]
3 years ago
5

Select the pair of consecutive integers between which a real zero of f(x) = x^3 + 5x^2 –x – 6 exists.

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0
<span>f(x)=0 at 
rounded up 
-4.96 
-1.1 
1.1</span><span>
</span>
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KN is perpendicular bisector of MQ identify the value of x
ExtremeBDS [4]

Answer:

x = 6

Step-by-step explanation:

Since KN is the perpendicular bisector, that means ∠KNM = ∠KNQ = 90° and MN = NQ so therefore, since they are right triangles, ΔKNM ≅ ΔKNQ because of HL. Therefore, KM = KQ by CPCTC so:

5x - 3 = 3x + 9

2x = 12

x = 6

4 0
3 years ago
Plz somebody help. ^_^
pickupchik [31]

Answer:

sin θ =  15/17

Step-by-step explanation:

First we have to know how much the hypotenuse measures.

to take out the hypotenuse we will use pitagoras, with the following formula.

h^2 = c1^2 + c2^2

c1 = 8

c2 = 15

h^2 = 8^2 + 15^2

h^2 = 64 + 225

h = √ 289

h = 17

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin θ = o/h

cos θ= a/h

tan θ = o/a

we want to know the sin of θ

sin θ = o/h

sin θ =  15/17

5 0
3 years ago
Help me p,ease please pleas please
Misha Larkins [42]

Answer:

O There are 28 chickens for every 1 chicken coop.

Step-by-step explanation:

5 0
2 years ago
The sum of two consecutive even numbers is 210.
WITCHER [35]

Answer:

104, 106

Step-by-step explanation:

Hello!

A consecutive number is a number that comes after the other.

Let the first even integer be x. Since there is an even integer for every two integers, the second number should be x + 2.

<h3>Solve for x</h3>
  • (x) + (x + 2) = 210
  • x + x + 2 = 210
  • 2x + 2 = 210
  • 2x = 208
  • x = 104

The second number is x + 2, so it would be 106.

6 0
2 years ago
Read 2 more answers
Write “ The difference between n and 16 is 5” is in algebraic equation. Then find the solution.
IceJOKER [234]
The different between n and 15 is 5 in an algebraic expression would be n-16=5
the solution would be n=21
5 0
3 years ago
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