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jok3333 [9.3K]
1 year ago
9

I need help on this one i will give 30 points

Mathematics
1 answer:
Ronch [10]1 year ago
3 0

Volume = area of cross-section x length

= 7 1/3 x 2

= 22/3 x 2/1

= 44/3

= 14 2/3

= 14.666666667

V = 44/3 (or 14 2/3, double of 7 1/3)

Hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago
The table shows information about all students doing GCSE's at a school.
PilotLPTM [1.2K]

Answer:

it's 3/5

Step-by-step explanation:

\frac{240}{400}  \frac{ \div }{ \div }  {4}  =  \frac{6}{10}  \frac{ \div }{ \div } 2 =  \frac{3}{5}

6 0
4 years ago
In a scale drawing of a house, 2 inches : 5 feet. The actual kitchen of the house will be 17 feet long. How long will the drawin
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I think it's 5.2 feet :))))

6 0
3 years ago
Yeah I need help with this
Mkey [24]

Answer:

$195 in total

Step-by-step explanation:

You would find the perimeter of the total garden first which equals 54 then times it by 1.5 and get 81 dollars for the gate. Then find the area of the triangle and get 120 then do 2 times 16 and get 32 then you add them together and get 152. Now with the 152 you divide it by 8 then multiple by 6 and finally add your 81 with 114 and get 195 dollars in total.

3 0
3 years ago
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2 more questions thanks
sergey [27]
These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2

                 k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2

Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

4 0
3 years ago
Read 2 more answers
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