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Rina8888 [55]
4 years ago
10

Which of the following is the slope of line perpendicular to the y= -2/3x + 5? A.2/3 B.3/2 C.-2/3 D.-3/2

Mathematics
1 answer:
Fofino [41]4 years ago
8 0

Answer:

+3/2 (Answer B)

Step-by-step explanation:

If the slope of a given line is m, then the slope of any line perpendicular to this given line is the negative reciprocal of the slope of the latter:

     -1

------------ = +3/2 (Answer B)

   -2/3

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
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Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

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Nookie1986 [14]

Answer:

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Step-by-step explanation:

I just checked on a calculator

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Step-by-step explanation:

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Step-by-step explanation:

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