Question

What is the directrix of a parabola whose equation is (y+3)^3=8(x-3)?

Answer 1

Considering the equation of the parabola, the directrix is: x = 1.

What is the equation of a parabola given it’s vertex?

The equation of an horizontal parabola, of vertex (h,k), is given by:

(y - k)² = 4p(x - h).

The directrix is at x = h - p.

For this problem, the equation is:

(y + 3)² = 8(x - 3).

The relevant coefficients for this problem are:

4p = 8 -> p = 2, h = 3.

Hence the directrix is:

x = h - p = 3 - 2 = 1.

More can be learned about the equation of a parabola at brainly.com/question/17987697

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Answer 2

The equation of the parabola whose equation $(y + 3)^3 = 8(x - 3).$, the directrix exists x = 1.

What is the equation of a parabola given its vertex?

The equation of a horizontal parabola, of vertex (h, k), exists given by:

(y - k)² = 4p(x - h).

The directrix exists at x = h - p.

For this problem, the equation exists:

$(y + 3)^3 = 8(x - 3).$

The appropriate coefficients for this problem exist:

4p = 8

p = 8/4 = 2 and h = 3.

Hence the directrix exists:

x = h - p = 3 - 2 = 1.

Therefore, the directrix exists at x = 1.

To learn more about the equation of a parabola refer to:

brainly.com/question/17987697

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