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NARA [144]
3 years ago
5

Solve the following equation for y, and then identify the slope of the line: 9x-3y=15

Mathematics
2 answers:
sashaice [31]3 years ago
5 0
9x-3y=15\ \ \ | subtract\ 9x\\\\
-3y=-9x+15\ \ \ | divide\ by\ -3\\\\
y=3x-5\\\\
y=ax+b\ \ a-\ slope\\\\
a=3\\\\Slope\ is\ equal\ to\ 3.
Ulleksa [173]3 years ago
5 0
9x-3y=15
-9x       -9x
-3y=-9x+15
/-3     /-3

y=3x-5

slope=3
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Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

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Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

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Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

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\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

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3 years ago
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