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DerKrebs [107]
1 year ago
12

The mass, m kilograms, of a horse is 429 kg, correct to the nearest kilogram.

Mathematics
2 answers:
Liula [17]1 year ago
6 0

Answer:

400 < m< 430 kg

Step-by-step explanation:

the mass of horse is 429 kg

estimated to the nearest hundred is 400  kg

estimated to the nearest  tens is 430 kg

thus the value of m mass lies between 400 to 430

therefore

400 < m< 430 kg

OverLord2011 [107]1 year ago
6 0

The answer is 400 < m< 430 kg

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2x^2y^2 - 7xy + 5y^2 + 8xy - 3y^2 + x^2y^2 + 4y^2

3x^2y^2 - 7xy + 5y^2 + 8xy -3y^2 + 4y^2

3x^2y^2 + xy + 5y^2 - 3y^2 + 4y^2

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3 years ago
Find the values of P for which the quadratic equation 4x²+px+3=0?​
klasskru [66]
<h3><u>Correct Questions :- </u></h3>

Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .

<h3><u>Solution</u>:- </h3>

Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

For equal roots

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\quad\green{ \underline { \boxed{ \sf{Discriminant, D = β² - 4αc}}}}

So,

\sf{  β² - 4αc = 0}

Here,

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Now,

\begin{gathered}\implies\quad \sf  p²- 4 \times 4 \times 3 =0 \end{gathered}

\begin{gathered}\implies\quad \sf  p²- 48 =0 \end{gathered}

\begin{gathered}\implies\quad \sf  p²=48\end{gathered}

\begin{gathered}\implies\quad \sf  p=±\sqrt{48}\end{gathered}

\begin{gathered}\implies\quad \sf  p=±\sqrt{2 \times 2 \times 2 \times 2 \times 3} \end{gathered}

\begin{gathered}\implies\quad \sf  p=± 2\times 2\sqrt{ 3 }\end{gathered}

\begin{gathered}\implies\quad \boxed{\sf{p=±4\sqrt{ 3 }}}\end{gathered}

Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-

4√3 and -4√3.

7 0
2 years ago
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Lunna [17]

Answer: SECOND OPTION

Step-by-step explanation:

You can solve the system of equations by the method of substitution:

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Therefore, you obtain:

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4 0
3 years ago
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Answer:

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Answer:

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2 years ago
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