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kenny6666 [7]
1 year ago
14

A trout was swimming 9 feet below the surface of a lake. It dove down 8 more feet to search for food. What is the position of th

e trout now relative to the surface?
To solve the problem, Denise subtracted
–
9–8 and came up with an answer of
–
17 feet. Is Denise correct? Why or why not?
Mathematics
1 answer:
RSB [31]1 year ago
3 0

The position of the trout now relative to the surface is -17 feet. Therefore, Denis is wrong.

<h3>What is an expression?</h3>

It should be noted that a expression shows the relationship between the variables.

From the information, a trout was swimming 9 feet below the surface of a lake and it drove down 8 more feet to search for food.

The position will be the addition of the feets. This will be:

= -9 + (-8)

= -9 - 8

= -17 feet

The position is -17 feet.

Learn more about expressions on:

brainly.com/question/723406

#SPJ1

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Order the decimals from least to greatest 3.4897, 3.3487, 1.5467, 3.348
Anna71 [15]

Answer:

1.5467, 3.348, 3.3487, 3.4897

Step-by-step explanation:

Remember to compare each one number at a time!

For the first number, only one number is 1 while the others are 3 making it the lowest.

Then when comparing 3.348 and 3.3487, it can be implied that there is a 0 at the end of 3.348 because it makes the numbers have the same # of decimal places without changing the value of the number (3.3480). That number is less than 7.

Finally, 3.4897 has a 4 in the tenths place instead of a 3 making it the highest number.

Hope this helps!

5 0
4 years ago
Determine whether each equation is True or False. In case you find a "False" equation, explain why is False.​
elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) \sqrt{32} = 2^{\frac{5}{2} }

2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ =  \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}

Thus, the equation is TRUE.

(2) 16^{\frac{3}{8} } = 8^2

16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64

Thus, the equation is FALSE.

(3) 4^{\frac{1}{2} } = \sqrt[4]{64}

4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64}  = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2}  \times \sqrt{2}  \times \sqrt{2} ) = 2\sqrt{2}

Thus, the equation is FALSE.

(4) 2^8 = (\sqrt[3]{16} )^6

2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256

Thus, the equation is TRUE.

(5) (\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\

8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4

Thus, the equation is FALSE.

4 0
3 years ago
Someone help me pls and thanks
shusha [124]

Answer: Mass is how much stuff something is made of. Volume is how much space an object takes up.

4 0
3 years ago
3(n+4)=21 what does n =?
Brilliant_brown [7]

Answer:

3.

Step-by-step explanation:

3(n + 4) = 21

3n + 12 = 21

3n = 21 - 12 = 9

n = 3.

7 0
3 years ago
Read 2 more answers
A group of students were asked how many times they exercised in the past week. The results were: 0,0,0,0,0,1,1,1,1,1,1,2,2,2,2,3
Digiron [165]

Answer:

Kindly check attached picture for histogram plot

Step-by-step explanation:

Given the data:

0,0,0,0,0,1,1,1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4,4,5,6,7,7,7

The range [0,2), [2,4), is the same as ;

Class range __ frequency

0 - 1 __________ 11

2 - 3 __________ 8

4 - 5 __________ 6

6 - 7 __________ 4

Kindly see picture for histogram plot

5 0
3 years ago
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