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ahrayia [7]
1 year ago
12

the graduate record exam (gre) is a standardized test which serves as an admission requirement for many graduate schools, and ha

s an analytic writing section and two multiple choice sections: verbal reasoning and quantitative reasoning. due to forced normalization in scores, both sections are approximately normal. the mean score for verbal reasoning section was 462 with a standard deviation of 119, and the mean score for the quantitative reasoning was 584 with a standard deviation of 151.
Mathematics
1 answer:
True [87]1 year ago
6 0

main answer : the normal distribution of given graduate record  exam is 1,A(1)=0.3413

supporting answer:Because of its flared shape, a graphical representation of a normal distribution is sometimes referred to as a bell curve. The precise shape varies depending on the population distribution, but the peak is always in the middle and the curve is always symmetrical. The mean, mode, and median of a normal distribution are all the same.

body of the answer: given that x₁=mean+standard deviation

                                     given mean₁=462

                                                standard deviation =119

  x₁=462+119=581

  z₁=581-462/119=1

  A(1)=0.3413

given mean₂=584

        standard deviation=151

x₂=584+151

   =735

z₂=735-584/151

  =1

A(1)=0.3413

final answer:there fore both scores are normal

to learn more about normal distribution link

brainly.com/question/23418254#:~:text=Expert%2DVerified%20Answer&text=Most%20values%20are%20close%20to%20the%20mean%20value.,curve%20called%20the%20normal%20curve.

#SPJ4

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Answer:

3.5

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

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\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

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\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

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Now the probability that exactly k bulbs need replacement is

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<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

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3 years ago
Mr jones is planning to pant grass and place afence in a small area for his dog. The rectagular dimension are 12×15 feet. The gr
goldenfox [79]

Answer:

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572

Step-by-step explanation:

Given as :

The dimension of rectangular field

Length of rectangular field = L = 12 feet

width of rectangular field = w = 15 feet

The cost of grass per square foot = 50 cents = $0.5    ( ∵ 1 cents = $0.01 )

The cost of small fence = $8 per linear foot

Now, According to question

A ) Let The total feet needed for the fence total perimeter = A feet

∵ Perimeter of rectangular field = 2 × Length + 2 × width

Or, A = 2 × L + 2 × w

Or, A = 2 × 12 feet + 2 × 15 feet

Or, A = 24 feet + 30 feet

∴ A = 54 feet

So, The total feet needed for the fence total perimeter = A = 54 feet

B ) Let The total cost of fence = $B

So, The total cost of fence = The cost of small fence × perimeter of fence

i.e B = $8 × 54 feet

∴ B = $432

So,The total cost of fence = B = $432

C) Let the square feet of grass needed foe the total area = C square feet

∵The Area of rectangular fence = Length × width

Or, The square feet of grass needed foe the total area = Area of rectangular fence = L × w

i.e C = 12 feet × 15 feet

Or, C = 180 feet²

So,The square feet of grass needed foe the total area = C = 180 square feet

D) Let The total cost of grass = $D

∵ The cost of grass per square foot = $0.5

So,Total cost of grass = $0.5 × Area of fence

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Or, D = $90

So, The Total cost of grass = D = $90

E) Let the total cost of the project = $E

∵Mr. Jones spend additional $50 for tools

So, The total cost of the project =  money spent on tools + total cost of fence + Total cost of grass

i.e E = $50 + B + D

Or, E = $50 + $432 + $90

∴ E = $572

So, The total cost of the project = E = $572

Hence,

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572  Answer

3 0
3 years ago
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fgiga [73]

Answer:

there is no question I'm sorry but I will take brainlyist

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3 years ago
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