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WINSTONCH [101]
3 years ago
7

Can someone help me I'm lost

Mathematics
2 answers:
arsen [322]3 years ago
5 0

Remark

The slopes of perpendicular lines = -1 when multiplied together. So you represent this as m1 * m2 = - 1. This formula applies if and only if the lines are perpendicular.

So in this case if m1 = 2/5

then m2 can be found as

m1 * m2 = - 1

2/5 * m2 = - 1 Multiply both sides by 5

2*m2 = -1 * 5 = - 5 Now divide by 2

m2 = -5/2

Answer: A


RUDIKE [14]3 years ago
4 0
The slopes of two perpendicular lines are opposite reciprocals meaning they are reciprocals like 2 and 1/2 you can either put the integer under one as a fraction or flip the numerator and denominator if the slope that you have is already a fraction then change the sign
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At hoffman's bike rentals,it cost $35 to rent a bike for 7 hours .How many hours of bike does the customer get per dollar?please
inysia [295]

Answer:

your answer is 5 dollars per hour

Step-by-step explanation:

35/7 = 5

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3 years ago
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What is the equation in point-slope form of a line perpendicular to y= ⅕ x+8, through the point (-2, 3) *
ivolga24 [154]

Answer:

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Step-by-step explanation:

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6+4+5+3 = 18

6th graders : total

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4 0
4 years ago
I need help on this???
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Use the geometric mean for right triangles here.  Like this \frac{9}{y}= \frac{y}{7}.  Cross multiply to get y^{2}=63, and y= \sqrt{63}.  That simplifies down to y= \sqrt{9*7}.  Pull out the 9 as a perfect square of 3 and you're left with y=3 \sqrt{7}, first choice above.
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Rufina [12.5K]
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3 years ago
Are AB and CD parallel, perpendicular, or neither?*<br> 1. A(-4, 8), B(4, 10), C(1, 1), D(-2, 13)
ohaa [14]

Answer:

Perpendicular

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Step-by-step explanation:

Given

A = (-4, 8)

B = (4, 10)

C = (1, 1)

D = (-2, 13)

Required

Is AB and CD parallel?

First, we need to calculate the slope (m) of AB and CD

m = \frac{y_2 - y_1}{x_2 - x_1}

For AB:

A (x_1,y_1)= (-4, 8)

B(x_2,y_2) = (4, 10)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10 - 8}{4 - (-4)}

m = \frac{10 - 8}{4 +4}

m = \frac{2}{8}

m = \frac{1}{4}

For CD:

C(x_1,y_1) = (1, 1)

D(x_2,y_2) = (-2, 13)

So:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{13 - 1}{-2 - 1}

m = \frac{12}{-3}

m = -4

For Lines to be parallel, the slope must be equal:

i.e. m_1 = m_2

This condition is not true because:

\frac{1}{4} \neq -4

For Lines to be perpendicular, the slope must be:

m_1 = -\frac{1}{m_2}

This implies:

\frac{1}{4} = -\frac{1}{-4}

\frac{1}{4} = \frac{-1}{-4}

\frac{1}{4} = \frac{1}{4}

<em>Hence, the lines are perpendicular</em>

6 0
3 years ago
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