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matrenka [14]
2 years ago
10

The following table shows the cost for a person to go to the 4 - H Fair to go on a certain number of rides: Develop an equation

to represent the scenario. A. y = 2x + 5B. y = 6x C. y = -2.5xD. y = 8x + 26E. None of the above

Mathematics
1 answer:
PtichkaEL [24]2 years ago
3 0

In order to develop an equation, let's use the slope-intercept form of the linear equation:

y=mx+b_{}

Using the points (3, 13.5) and (5, 18.5) from the table, we have:

\begin{gathered} (3,13.5)\colon \\ 13.5=3m+b \\ (5,18.5)\colon \\ 18.5=5m+b \end{gathered}

Subtracting the second and the first equation:

\begin{gathered} 5m+b-(3m+b)=18.5-13.5 \\ 2m=5 \\ m=2.5 \end{gathered}

Now, finding the value of b:

\begin{gathered} 13.5=3m+b \\ 13.5=7.5+b \\ b=13.5-7.5 \\ b=6 \end{gathered}

So the equation that represents this table is y = 2.5x + 6

Looking at the options, the correct one is E (none of the above).

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3 years ago
Please help me!!!!!!!!!!!!!!
OLga [1]

Answer:

  1. d, series and sequence diverge
  2. d, geometric/divergent
  3. c, e (geometric, |r|<1)

Step-by-step explanation:

<h3>1.</h3>

The sequence terms have a common difference of -5/8. That make it a non-trivial arithmetic sequence, so it diverges.

The series is the sum of terms of the sequence. Any non-trivial arithmetic series diverges.

(A "trivial" arithmetic series has a first term of 0 and a common difference of 0. It is the only kind of <em>arithmetic</em> series that doesn't diverge.)

__

<h3>2.</h3>

The terms of the series have a common ratio of -2. That makes it a geometric series. The ratio magnitude is greater than 1, so the series diverges.

__

<h3>3.</h3>

A sequence will converge only if the terms have a common difference of 0 or a common ratio with a magnitude less than 1. Of the offered choices, only C and E will converge:

  c. geometric, r = 3/5

  e. geometric, r = -1/6

_____

<em>Additional comment</em>

The convergence criteria stated for problem 3 applies only to arithmetic and geometric sequences. There are many other kinds of sequences that converge, but these are the kinds being considered in this problem set.

3 0
2 years ago
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