The width would be x-4 and
Length would be x
Add all of the sides together
(x-4)+(x-4) + x + x =72,
Which would come out
4x-8=72
Subtract 8 fro, 72 and you get 64
Then divided 64 by 4
So. Width is 16 and length is 20 . given (x-4)
Answer:
f(x) = 2(x -3)² +5 or f(x) = 2x² -12x +23
Step-by-step explanation:
The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.
__
<h3>vertex form</h3>
The vertex form equation for a parabola is ...
f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'
<h3>equation</h3>
For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...
f(x) = 2(x -3)² +5 . . . . . vertex form equation
Expanded to standard form, this is ...
f(x) = 2(x² -6x +9) +5
f(x) = 2x² -12x +23 . . . . . standard form equation
1. a²+b²=c²
a=6²=36
b=x²
c=15²=225
x=√189 feet deep (the square root of 189)
2. a²+b²=c²
a=3²=9
b=x²
c=5²=25
x=√16=4
Hope that helped
;)
Answer:
A = 0.25*j + 1
Step-by-step explanation:
The question presented here is an application of linear models. The $1 amount is fixed and does not depend on any factor such as the cups of orange juice sold.
Furthermore, we are informed that we earn $0.25 for every cup of orange juice sold. This means that we shall earn 0.25 j by selling j cups of orange juice.
The variable total amount, A will thus depend on the fixed amount of $1 and the variable income 0.25 j.
The equation in two variables that will represent the total amount A (in dollars) you have after selling j cups of orange juice will thus be;
A = 0.25*j + 1
<em>Hope this helped.....</em>
Answer:
Remember that:
Speed = distance/time.
Then we can calculate the average speed in any segment,
Let's make a model where the average speed at t = t0 can be calculated as:
AS(t0) = (y(b) - y(a))/(b - a)
Where b is the next value of t0, and a is the previous value of t0. This is because t0 is the middle point in this segment.
Then:
if t0 = 100s
AS(100s) = (400ft - 0ft)/(200s - 0s) = 2ft/s
if t0 = 200s
AS(200s) = (1360ft - 50ft)/(300s - 100s) = 6.55 ft/s
if t0 = 300s
AS(300s) = (3200ft - 400ft)/(400s - 200s) = 14ft/s
if t0 = 400s
AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s
So for the given options, t = 400s is the one where the velocity seems to be the biggest.
And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.
Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.
