All categories

1 year ago

Twice a number, increased by three, is between negative one and nine. Find all the numbers.

Mathematics

1 answer:

pashok25 [27]1 year ago

8 0

The solution set for the obtained inequality is {.......-5, -4, -3, -2, -1, 0, 1, 2}.

Given that, twice a number, increased by three, is between negative one and nine.

<h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than’, or < ‘less than’.

Let the unknown number be x.

Now, twice a number, increased by three = 2x+3

The given expression is between negative one and nine

-1 < 2x+3 < 9

-1 < 2x+3

Subtract 3 to both the side of the inequality

-1-3<2x+3-3

⇒ -4 < 2x

Divide 2 to both the side of the inequality

-2 < x

Now, 2x+3 < 9

Subtract 3 to both the side of the inequality

2x+3-3<9-3

⇒ 2x<6

Divide 2 to both the side of the inequality

x < 3

So, -2<x<3

Solution set = {.......-5, -4, -3, -2, -1, 0, 1, 2}

Therefore, the solution set for the obtained inequality is {.......-5, -4, -3, -2, -1, 0, 1, 2}.

To learn more about a inequality visit:

brainly.com/question/20383699.

#SPJ1

You might be interested in

Which expression is equivalent to 6 minus (negative 8)?Negative 6 + 8Negative 6 + (negative 8)6 + (negative 8)6 + 8

Lerok [7]

Answer:

Negative 6) (4) + (negative 6) (two-thirds)

(Negative 6) (4) times (negative 6) (two-thirds)

(Negative 6 + 4) + (Negative 6 + two-thirds)

(Negative 6 + 4) times (negative 6 + two-thirds)

himselfvlix

Answer is A

Step-by-step explanation:

4 0

4 years ago

PLEASE HELP ME FAST!! GIVING MANY POINTS . Show all work

DanielleElmas [232]

Answer:

sin(θ) = √65/9

tan(θ) = √65/4

sec(θ) = 9/4

csc(θ) = 9/√65 = (9√65)/65

cot(θ) = 4/√65 = (4√65)/65

Step-by-step explanation:

Let's first define all these trigonometric functions:

- sine (sin) = opposite / hypotenuse

- cosine (cos) = adjacent / hypotenuse

- tangent (tan) = opposite / adjacent

- secant (sec) = hypotenuse / adjacent

- cosecant (csc) = hypotenuse / opposite

- cotangent (cot) = adjacent / opposite

We know that cos(θ) = 4/9, where 4 is the adjacent and 9 is the hypotenuse. We can make this into a right triangle (see attachment), where one of the legs is 4, the hypotenuse is 9, and the last leg is √(9² - 4²) = √(81 - 16) = √65. That means the opposite is √65.

We can now solve for all the rest of the trigonometric functions:

sin(θ) = √65/9

tan(θ) = √65/4

sec(θ) = 9/4

csc(θ) = 9/√65 = (9√65)/65

cot(θ) = 4/√65 = (4√65)/65

3 0

4 years ago

The altitude of an airplane is decreasing at a rate of 42 feet per second. What is the change in altitude of the airplane over a

stira [4]

Answer:

D. -924 feet

Step-by-step explanation:

<h3><u>Necessary formula</u></h3>

For this problem, we'll need the relationship $d=vt$ where "d" is the distance traveled, "v" is the velocity the object is traveling, and "t" is the amount of time that it traveled.

<h3><u>Velocity Vectors</u></h3>

Velocity is a "vector" quantity, which has both a magnitude and a direction. The magnitude is the speed (42 feet per second) and the direction is downward. Collectively, the velocity is -42 feet per second. This will address the change in altitude and signify that the change in altitude is downward.

<h3><u>Units</u></h3>

All quantities should be using units that match.

In this case, the <u>distances</u> provided in the answers are all measured in <u>feet</u>, and the speeds are measured in <u>feet</u> per second, so the feet match.

Also, the <u>times</u> are measured in <u>seconds</u>, and the speeds are measured in feet per <u>second</u>, those also match.

<h3><u>Substitution & solve</u></h3>

<u /> $d=vt$

$d=(\frac{-42\text{ feet}}{\text{second}})(22\text{ seconds})$

$d=-924 \text{ feet}$

5 0

2 years ago

F(x) = x^3 - 5x^2 - x ; find f(3)

Wewaii [24]

Answer:

Here is your answer

Step-by-step explanation:

Question: f(x)= x³-5x²-x

Answer:. f(3)=3³-5 x 3³ -3

f(3)=27 -135 -3

f(3)=27-138

f(3)=-111

hope this helps you

please mark me brainliest

have a great day :)

3 0

2 years ago

The quotient of j and 8

Ludmilka [50]

J/8 is the answer youre looking for

5 0

3 years ago

Twice a​ number, increased by ​three, is between negative one and nine. Find all the numbers.

Twice a number, increased by three, is between negative one and nine. Find all the numbers.