Question

1/6+2/3=1/4(d-2) solve equation and check solution

Answer 1

1) Let's solve this equation, and then check it. Let's find the LCM of 6, 3 which is 6

$\begin{gathered} \frac{1}{6}+\frac{2}{3}=\frac{1}{4}(d-2) \\ \frac{1}{6}+\frac{4}{6}\text{ =}\frac{d-2}{4} \\ \frac{5}{6}=\frac{d-2}{4} \\ \text{Cross Multiply this:} \\ 6(d-2)\text{ =20} \\ \text{DIvide both sides by 6} \\ d-2\text{ =}\frac{10}{3} \\ 3(d-2)\text{ =10} \\ 3d\text{ -6=10} \\ 3d=16 \\ d=\frac{16}{3} \end{gathered}$

2) Checking it, we'll have:

$\begin{gathered} \frac{5}{6}=\frac{(d-2)_{}}{4} \\ \frac{5}{6}=\frac{\frac{16}{3}-2}{4} \\ \frac{5}{6}=\frac{5}{6\text{ }} \end{gathered}$