All categories

3 years ago

WILL MARK BRAINLIST PLSSSSSSSSS

Mathematics

1 answer:

larisa [96]3 years ago

3 0

Answer:

Answer

Step-by-step explanation:

I believe it is the first or second choice. I believe it is the first choice, but it could be the second one.

Sorry hope it helps.

You might be interested in

What is the midpoint of 18.6 and 18.5?

Nina [5.8K]

The midpoint of 18.6 and 18.5 is 18.55

5 0

3 years ago

Lynn is a single mother with two children's . She qualifies to file as head of household her total income was $27267 last year h

storchak [24]

Answer:

$3,078.04

Step-by-step explanation:

-Given her income is $27,267, she falls under the 10% and 12% brackets with the following boundaries as attached.

-Her tax is then calculated as;

#10% bracket;

$Tax=Taxable \ Income \times Tax \ Rate\\\\=9700\times 10\%\\\\\\=\$970.00$

#12% Tax bracket:

$Tax=Taxable \ Income \times Tax \ Rate\\\\=(27267-9700)\times 12\%\\\\\\=\$2108.04$

The total tax=970+2108.04=$3,078.04

Hence, Lynn owes $3,078.04 in taxes.

7 0

3 years ago

Heeeelp just need 1 and 3

Harlamova29_29 [7]

Answer: I think the answer is. x=y*z I dont know what the verbles are but thats what I got. ANd can you zoom in a bit?

Step-by-step explanation:

4 0

3 years ago

How to do this equation 2 radical 6 minus 3 radical 6

Slav-nsk [51]

$\bf \stackrel{like-terms}{2\sqrt{6}-3\sqrt{6}}\implies -1\sqrt{6}\implies -\sqrt{6}$

6 0

3 years ago

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0

3 years ago