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Scrat [10]
1 year ago
9

HELPPPP which value is equal to 2✓28-5✓63?a-37✓7b-✓7c-11✓7d✓7​

Mathematics
1 answer:
IrinaVladis [17]1 year ago
7 0

Answer:

c

Step-by-step explanation:

if I understand this right, then the expression is

2×sqrt(28) - 5×sqrt(63)

let's look for squared factors in the numbers under the square roots.

28 = 4×7 (4 is a squared number)

63 = 9×7 (9 is a squared number)

so,

2×sqrt(4×7) - 5×sqrt(9×7) =

= 2×2×sqrt(7) - 5×3×sqrt(7) = 4×sqrt(7) - 15×sqrt(7) =

= (4 - 15)×sqrt(7) = -11×sqrt(7)

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If you help me just explain it to me
love history [14]

Answer:

C

Step-by-step explanation:

lets find median 2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

now lets find the lower quartile median and upper quartile median

we don't include the median in the count, only use it to divide the data into the two parts,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, 10, 13, 17

so lower quartile median is 4,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, <u>10</u>, 13, 17

while upper quartile median is 10

the box represents the range between the upper quartile median and lower quartile median, thus is should go from 4 to 10 with the middle line, representing the median at 8,

the whiskers represent the whole data range

thus, the answer is C

6 0
3 years ago
Solve 7 times 7 times 7 times 7​
lukranit [14]

hope it helps you......

8 0
3 years ago
Read 2 more answers
Find the surface area of the regular pyramid.
spayn [35]

Answer:

Answer = 93.6

Step-by-step explanation:

frist multipy 9 x 13 to get 117 than divided it by 2 = 58.5, than times it by 3 since there is three sides.

(58.5 x 3 is 175.5)      

Than for the base multipy 7.8 x 9 = 70.2, but since its a tri, divided it by 2 = 35.1.

Add 58.5 and 35.1 to get 93.6

5 0
2 years ago
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Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
1 year ago
Factor f(x)=x^(3)-2x^(2)-x+2
DanielleElmas [232]
X=-1
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if wrong sorry
6 0
2 years ago
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