Answer:
f(7) = 158
Step-by-step explanation:
To evaluate f(7) substitute t = 7 into f(t)
f(7) = 3(7)² + 11 = (3 × 49) + 11 = 147 + 11 = 158
A) 2(1+2c)
2+4c = 2+4c
B) 6(14r-2t)
= 84r-12t
What is the math problem?
Answer:
5.25 times
Step-by-step explanation:
Beverage A and Beverage B are sold in identical cans.
From the above question
Beverage A is 4% sugar.
The portion of Beverage B that is sugar is 0.21.
Converting Portion of sugar in Beverage B to percentage we have :
0.21 × 100
= 21%
How many times more sugar is in Beverage B than Beverage A?
This is calculated as:
% Beverage B/% Beverage A
= 21%/4%
= 5.25
Hence Beverage B has 5.25 times more sugar than Beverage A.
