Question

Makayla was scuba diving. She started at at-80 5/9 meters below the surface. She then swam up 20 2/9 meters from her storting location for a break. Alwhat location did she stop for her break compared to sea level?

Answer 1

Answer:

543/9 meters below the surface.

Explanation:

First, we need to transform the mixed numbers into fractions, so 80 5/9 meter and 20 2/9 meters are equivalent to:

$\begin{gathered} A\frac{b}{c}=\frac{A\cdot c+b}{c} \\ 80\frac{5}{9}=\frac{80\cdot9+5}{9}=\frac{725}{9} \\ 20\frac{2}{9}=\frac{20\cdot9+2}{9}=\frac{182}{9} \end{gathered}$

Now, to calculate the location where she stops for a break, we need to take 182/9 and subtract it from 725/9. So:

$\frac{725}{9}-\frac{182}{9}=\frac{725-182}{9}=\frac{543}{9}$

Therefore, Makayla stops for a break at 543/9 meters below the surface.