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kiruha [24]
3 years ago
14

Parallel and Perpendicular Lines

Mathematics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

neither; perpendicular; parallel; neither; neither

Step-by-step explanation:

parallel line is where the 2 slopes have same gradient and perpendicular means the two lines have a -1 slope when producted

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks! (I'll be uploading tips on parallel and perpendicular lines soon today!)

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Find all of the critical points of p (t). p (t) = t 2 + 5t + 6.
svp [43]

Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.

To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:

p '(t) = 2t + 5 = 0

Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.

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What is the distance formula and how do i do it
stiv31 [10]

Answer: What is the distance formula is that it's the formula used in Mathematics such as Pre-Algebra, Algebra 1, Geometry, Algebra 2, Trigonometry, and Pre-Calculus, also Calculus to help you find the distance between 2 points in a coordinate plane or the length of a segment. How you do the distance formula is you subtract the 2nd x coordinate by the 1st one, next you add the 2nd y coordinate to the 1st one, then the answer you get you evaluate them using the exponent of 2, lastly you add that answer and square root the answer you get to the approximate or closest decimal or whole number.

7 0
3 years ago
The graph below shows a company's profit f(x), in dollars, depending on the price of pens x, in dollars, sold by the company:
Volgvan

The answers to the various part as well as its reasons are given below

<h3 /><h3>Part A:</h3>
  • The x-intercepts shows a zero profit.
  • The maximum value of the graph tells  or depict the maximum profit.
  • The function is one that goes up or increases upward until it reach the vertex and then it falls or decreases after it.
  • This implies that the profit goes up as it reaches the peak at the vertex and it goes down after the vertex up until it gets to zero.
  • The  profits are negative as seen on the left of the first zero and on the right of the second zero.

<h3>Part B:</h3>

An approximate average rate of change of the graph from x = 3 to x = 5, shows the reduction in profit from  3 to 5.

<h3>Part C:</h3>

Based on the above,  the domain is one that is held back or constrained by x = 0 .

We are compelled at x = 6 due to the fact that we have to maneuver a negative profit.

Learn more about quadratic function from

brainly.com/question/25841119

#SPJ1

4 0
2 years ago
How would you verify the trigonometric identity 2x = 2sinx cosx
dem82 [27]

Step-by-step explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>sin2x</em><em>=</em><em>2</em><em>sinx</em><em> </em><em>.</em><em> </em><em>cosx</em>

<em>so</em><em>,</em><em> </em><em>let's</em><em> </em><em>begin</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>simple</em><em> </em><em>way</em><em>;</em><em> </em><em>by</em><em> </em><em>adding</em><em>,</em><em> </em><em>alright</em><em>:</em>

<em>sin2x</em><em>=</em><em> </em><em>sin</em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>2</em><em>x</em><em>=</em><em>x</em><em>+</em><em>x</em><em>)</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>let's</em><em> </em><em>use</em><em> </em><em>compound</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>sin</em><em>,</em>

<em>so</em><em>,</em><em> </em><em>we</em><em> </em><em>get</em><em>:</em>

<em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em> </em><em>sinx.cosx</em><em> </em><em>+</em><em> </em><em>cosx</em><em>.</em><em> </em><em>sinx</em><em> </em><em> </em><em> </em><em>(</em><em>as</em><em> </em><em>sin</em><em>(</em><em>A</em><em>+</em><em>B</em><em>)</em><em>=</em><em>sin</em><em> </em><em>A</em><em>.</em><em> </em><em>cosB</em><em> </em><em>+</em><em> </em><em>cosA</em><em> </em><em>.</em><em> </em><em>sinB</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>sin</em><em> </em><em>(</em><em>x</em><em>+</em><em>x</em><em>)</em><em>=</em><em>2</em><em>sinx</em><em>.</em><em>cosx</em><em> </em><em> </em><em>(</em><em>adding</em><em> </em><em>both</em><em>)</em><em>.</em>

<em>Therefore</em><em>, </em><em> </em><em>sin</em><em> </em><em>2</em><em>x</em><em> </em><em>=</em><em> </em><em>2sinx</em><em>.</em><em> </em><em>cosx</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Read 2 more answers
I need the answers for this question. I am confused
noname [10]

Answer:

Step-by-step explanation:

As C and D are both at y = -9, the line below V₂ is vertical and located at

x = ½(22 + (-2) = 10

The line between V₁ and V₂ will contain the point halfway between B and D.

x = ½(14 + (-2)) = 6

y = ½(7 + (-9)) = -1

(6, -1)

The slope of the line between V₁ and V₂ is the same as between V₁ and our just found midpoint between B and D

m = (5 - (-1)) / (0 - 6) = -1

so the line equation is

y = -x + 5

Which intersects x = 10 at

y = -10 + 5 = -5

V₂ = (10, -5)

The distance between V₂ and B, C, and D is

d = √((14 - 10)² + (7 - (-5))²) = √160

The distance between V₁ and B, A, and D is

d = √((-10 - 0)² + (15 - 5)²) = √200

As √200 > √160, the dump should be located at V₁ or at least √200 away from any two of the points

5 0
3 years ago
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