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nlexa [21]
1 year ago
8

I need assistance with "What does the area of the rectangle depend on", the graph section, and the relationship section.

Mathematics
1 answer:
DanielleElmas [232]1 year ago
7 0

The area equation here is:

A=2w^2

That means that the area depends on the width measurement of the rectangle.

To graph a quadratic function you have to see if the parabole is positive and the transformations, in this case, are positive and have a multiplication by two, which means that the graphics in x=1 and x=-1 will be y=2

Finally, you can conclude that there, you have a relationship between the area and the width of the rectangle because is a quadratic relationship and the area will increase in a quadratic form according to the increase of the width.

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The graph below shows Sean's distance, d, from his home (in kilometers) as a function of the time, t (in hours).
sdas [7]

Answer:

20

20

5

Step-by-step explanation:

4 0
2 years ago
WARNING : NON SENSE ANSWER REPORT TO MODERATOR ​
Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

  • Simplify (\frac{3}{-7} - \frac{11}{21} )

=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

  • Simplify (\frac{9}{5} \div \frac{7}{5} )

=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

=> \frac{9}{5} \times \frac{5}{7}

=> \frac{9}{7}

  • Now, find the product of \frac{9}{7} & \frac{20}{21}

=> \frac{9}{7} \times \frac{20}{21}

=> \frac{180}{147}

3 0
3 years ago
You have been cleanin diesel dispensers for 35 minutes you have completed 6 you hace completed 6 how many minutes its taken to c
ololo11 [35]
The answer is 5.833333333 or 5.83 minutes
7 0
3 years ago
a 23 gram sample of a substance thats a by-product of fireworks has a K-value of .13. whats the substances half life in days
nata0808 [166]
Given:
Initial mass, m₀ = 23 g
Decay constant, k = 0.13

Exponential decay obeys the equation
m(t)=m_{0} e^{-kt}
where t = time, days

For half life, the mass is m = m₀/2.
Therefore
e^{-0.13t} = \frac{1}{2} \\ -0.13t = ln(0.5)\\t= \frac{ln(0.5)}{-0.13} =5.33

Answer: The half life is 5.33 days
3 0
2 years ago
Read 2 more answers
The summit of a mountain pass is 8,050 ft above sea level. the valley below is 12 and 1/2 ft below sea level. what is the vertic
Veseljchak [2.6K]

Answer:

Vertical distance between the valley and the summit = 8062.5 ft

Step-by-step explanation:

Distances above the sea level are denoted by positive notations and below the sea level by negative notation.

Summit of a mountain pass = 8050 (above the sea level)

Valley below the sea level = 12 and half ft = (-12.5) ft

Distance between the summit and the valley = 8050 - (-12.5)

                                                                           = 8050 + 12.5

                                                                           = 8062.5 ft

Therefore, Vertical distance = 8062.5 ft will be the answer.

5 0
3 years ago
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