Answer:
The answer to the question is
The kinds of polygons that could be Diedre's quadrilateral are rectangle and square
Step-by-step explanation:
We note the conditions of the polygon as thus
Number of sides = 4, Which include trapezoid, square, rectangle
Size of angles = 90 ° which eliminates trapezoid
Sizes of opposite sides = Equal opposite sides, includes square and rectangle
With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square
Answer:
GH = 9 units
Step-by-step explanation:
Given HI = 4b - 5 and HI 3, then
4b - 5 = 3 ( add 5 to both sides )
4b = 8 ( divide both sides by 4 )
b = 2
Thus
GI = 5b + 2 = 5(2) + 2 = 10 + 2 = 12
GH = GI - HI = 12 - 3 = 9
The answer is 223.75 because you multiply 12.5 and 17.9
Answer:
A
Step-by-step explanation:
x² - 3x - 54 = 0
x² - 9x + 6x - 54 = 0
x(x - 9) + 6(x - 9) = 0
(x - 9)(x + 6) = 0
x = -6,9
Xcubed=y
Each slice was 2$ entrance fee was 4$