30 + 8d = 102
8d = 102 - 30
8d = 72
d = 72/8
d = 9....you would have to walk 9 dogs
Answer:
C = 106.76 cm
Step-by-step explanation:
In the diagram, we are given the diameter (d), which is 34 cm. Using the formula you are given, we know circumference is 3.14 × d
C = 3.14 × d
C = 3.14 × (34)
C = 106.76 cm
The circumference is around 106.76 cm
Answer:
The claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.
Step-by-step explanation:
Since an online health and medicine company claims that about 50% of Internet users would go to an online sight first for information regarding health and medicine, and a random sample of 1318 Internet users was asked where they will go for information the next time they need information about health or medicine; 606 said that they would use the Internet, to test the claim that less than 50% of Internet users get their health questions answered online, the following calculation must be performed:
1318 = 100
606 = X
606 x 100/1318 = X
60600/1318 = X
45.978 = X
Therefore, the claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.
Answer:
x is 6 because
y is 30
p is 120
Step-by-step explanation:
60 degrees and 10x are the same and 6×10 = 60
(4y) and 60 degrees must equal 180 so y has to be 30
(4y) and p are the same
Answer:
So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10
Step-by-step explanation:
Let X the random variable that represent the number of rookie cards of a population, and for this case we know the distribution for X is given by:
Where 
and 
We select a sample size of n = 10 variety packs and we want to find this probability:
We can use the z score formula given by:
If we apply this formula to our probability we got this:
We can find the z score for 2 and 4 and we got:
So we can find the probability with this difference
And using the normal standard distirbution or excel we got:
So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10
